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How much silver will be produced when 1 gram of silver nitrate solution reacts with copper?

The balanced equation for this reaction is:


       Cu + `~2AgNO_3` -> `~Cu(NO_3)_2` + 2Ag


Step 1: Determine the molar mass conversion factors for `~AgNO_3` and Ag.


The molar mass of a substance is calculated by multiplying the atomic mass of each element in a substance by its subscript and adding the resulting products together.


Molar Mass `~AgNO_3` : 1(107.968) + 1(14.007) + 3(15.999) = 169.972 g/mol


   Therefore, 1 mole = 169.972 grams `~AgNO_3`


Molar Mass Ag: 1(107.968) = 107.968 g/mol


   Therefore, 1 mole = 107.968 g Ag


Step 2: Determine the mole ratio between `~AgNO_3` and Ag.


The mole ratio is ratio between the coefficients of two substances in a chemical reaction.


The coefficient of `~AgNO_3` is 2.


The coefficient of Ag is 2.


Therefore the mole ratio is 2 moles `~AgNO_3` = 2 moles Ag.


Step 3:  Perform the stoichiometry calculation.


The stoichiometry calculation will take the general form:


 (given amount)(`~AgNO_3` conversion factor)(mole ratio)(Ag conversion factor)


Therefore,


(1.0g `~AgNO_3` )(1mol/169.972)(2mol Ag/2mol `~AgNO_3` )(107.968g/1mol)


   =  0.64 g Ag


*Notice that the conversion factors and mole ratio are oriented such that all units except "g Ag" cancel out.

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