`(4+tan^2(x))y'=sec^2(x)`
`=>y'=(sec^2(x))/(4+tan^2(x))`
`y=int(sec^2(x))/(4+tan^2(x))dx`
Apply integral substitution: `u=tan(x)`
`du=sec^2(x)dx`
`y=int1/(4+u^2)du`
`=int1/(u^2+2^2)du`
Use the standard integral :`int1/(x^2+a^2)dx=1/aarctan(x/a)`
`=1/2arctan(u/2)`
Substitute back u=tan(x) and a constant C to the solution,
`=1/2arctan(tan(x)/2)+C`
`y=1/2arctan(tan(x)/2)+C`
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