Given to solve
`int x^5 ln(3x) dx`
let `u= ln(3x) ,u' = (ln(3x))'`
=`(1/(3x))*(3) = 1/x`
so `u' = 1/x`
and `v'= x^5 => v= x^6/6 `
by applying the integration by parts we get,
`int uv' dx= uv - int u'v dx`
so,
`int x^5 ln(3x) dx `
=`(ln(3x))(x^6/6) - int (1/x)(x^6 /6) dx`
= `(ln(3x))(x^6/6) - (1/6) int (1/x)(x^6 ) dx`
=` (ln(3x))(x^6/6) - (1/6) int (x^5 ) dx`
= `(ln(3x))(x^6/6) - (1/6) int (x^5 ) dx`
= `(ln(3x))(x^6/6) - (1/6) [x^6 /6]+c`
= `ln(3x)x^6/6 - 1/36 x^6 +c`
= `x^6/6(ln(3x)-x^6/6) + c`
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