Evaluate `sum_(n=1)^(oo)nsin(1/n) `
This series diverges.
We use the limit test: if the series converges the limit of the nth term must be 0 as n grows without bound.
`lim_(n->oo)nsin(1/n)=1 `
We use L'Hopital's rule as we have the indeterminant form `oo * 0 `
`lim_(n->oo)n*sin(1/n)= `
`lim_(n->oo) sin(1/n)/(1/n) = 0/0`
Use L'Hopital's rule to get:
`lim_(n->oo) = (-cos(1/n)/(1/n^2))/(-1/n^2) = cos(1/n)`
`lim_(n->oo)cos(1/n)=1`
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