`m_1 = 8 , m_2 = 5 , m_3 = 5 , m_4 = 12 , m_5 = 2 , x_1 = -2 , x_2 = 6 , x_3 = 0 , x_4 = 3 , x_5 = -5` Find the center of mass of the point...

The center of mass is the unique point at the center of a distribution of mass in space. It has the property that the weighted position vectors relative to this point sum to zero.

It is given by;

Center of mass `= [sum_(i=1)^nm_ixxx_i]/(sum_(i=1)^nm_i)`

We have 5 point masses here.

Center of mass

`=[sum_(i=1)^5m_ixxx_i]/[sum_(i=1)^5m_i]`

`= (8xx(-2)+5xx6+5xx0+12xx3+2xx(-5))/(8+5+5+12+2)`

`= (-16+30+0+36-10)/(32)`

`= 40/32`

`= 5/4`

`= 1.25`

So the center of mass of the point masses lying on the x-axis is 5/4 or 1.25

Comments

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