`x/(x+1)=3/(x+1)`
cross multiply,
`x(x+1)=3(x+1)`
`x*x+x*1=3*x+3*1`
`x^2+x=3x+3`
`x^2+x-3x-3=0`
Factorize,
`x(x+1)-3(x+1)=0`
`(x+1)(x-3)=0`
use zero product property,
`x+1=0` or `x-3=0`
`x=-1` or `x=3`
Now let's check the solutions by plugging them in the original equation,
For x=-1
`(-1)/(-1+1)=3/(-1+1)`
`(-1)/0=3/0`
It's an extraneous solution, as it leads to division by zero.
For x=3,
`3/(3+1)=3/(3+1)`
`3/4=3/4`
It's true.
So, the solution of the equation is x=3
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