Evaluate ` sum_(n=1)^(infty)(2n+1)/(n^2(n+1)^2) `
Consider the sequence of partial sums:
n=1 3/4
n=2 3/4+5/36=8/9
n=3 3/4+5/36+7/144=15/16
n=4 3/4+5/36+7/144+9/400=24/25
The mth partial sum is given by ` 1-1/(m+1)^2 `
Since the limit of this expression as m grows without bound is 1, this will be the sum.
Thus the sum is 1.
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