`int_0^1 (2x-5)/(x^2-5x+6) dx`
The function
`f(x) = (2x-5)/(x^2-5x+6)`
is continuous on the interval `(-oo, 2) uu (2,3) uu (3,oo)` .
Since the limit of the integral is from x=0 to x=1, then the integrand is continuous on the interval [0,1].
Therefore, ` int_0^1 (2x-5)/(x^2-5x+6)dx` is a proper integral.
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