`ln40+2ln(1/2) + lnx`
First, apply the logarithm rule `log_b (a^m)=m*log_b(a)` .
`= ln40 + ln(1/2)^2 + ln x`
`=ln40+ ln(1/4) + lnx`
And, apply the rule `log_b(m*n) = log_bm +log_b n` .
`= ln (40 * 1/4*x)`
`=ln (10x)`
Therefore, `ln40+2ln(1/2) + lnx=ln(10x)` .
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