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`sum_(n=1)^oo (1+1/n)^n` Determine the convergence or divergence of the series.

If a series  `sum a_n`  converges, its term `a_n` tends to zero (the converse is not true in general). Thus if `a_n` does not tend to zero, the series is divergent.


For this series  `a_n = (1 + 1/n)^n,` which has a limit of `e approx 2.7.`  So this series diverges.

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