Members of a freshmen orientation class take a time management test. Their average time management score is 82, and the standard deviation for...
Standard error of the mean is given by the formula,
`sigma_m=sigma/sqrt(N)`
where `sigma` is the standard deviation of the original distribution,
and N is the sample size.
We have been given the standard deviation of the scores `sigma` as 6
Now let's calculate `sigma_m` for different sample sizes,
1) Sample size 25
`sigma_m=sigma/sqrt(N)`
Plug in the values in the formula,
`sigma_m=6/sqrt(25)`
`=6/5`
`=1.2`
2) Sample size 36
`sigma_m=6/sqrt(36)`
`=6/6`
`=1`
3) Sample size 49
`sigma_m=6/sqrt(49)`
`=6/7`
`=0.857`
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