`ln(4x-7)=ln(x+11)` Solve the equation. Check for extraneous solutions.

`ln(4x-7)=ln(x+11)`

Using one to one property of logarithms,

`4x-7=x+11`

`=>4x-x=11+7`

`=>3x=18`

`=>x=18/3`

`=>x=6`

Plug back the solution in the equation to check the solution,

`ln(4*6-7)=ln(6+11)`

`ln(24-7)=ln(17)`

`ln(17)=ln(17)`

So, its true.

Solution of the equation is 6.