`h(x)=log_5(x+1)-3` Graph the function. State the domain and range.

We are asked to graph the following function:

`y=log_5(x+1)-3`

The base function is

`y=log_5(x)`

and the graph will be a translation of 1 unit left and 3 units down of the graph of the base function.

The domain is x>-1 and the range is all real numbers. The graph is increasing everywhere and concave down on its domain.

Some points on the graph include: (-24/25,-5),(-4/5,-4),(0,-3),(4,-2),(24,-1)

The graph:

Comments

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