Solve `log_2(x+1)=log_8(3x) ` :
Rewrite using the change of base formula:
`(ln(x+1))/(ln(2))=(ln(3x))/(ln(8)) `
`(ln(8))/(ln(2))=(ln(3x))/(ln(x+1)) ` But `ln(8)=ln(2^3)=3ln(2) ` so:
`3=(ln(3x))/(ln(x+1)) `
`3ln(x+1)=ln(3x) `
`ln(x+1)^3=ln(3x) `
`(x+1)^3=3x `
`x^3+3x^2+1=0 `
The only real root is negative. Assuming that we are looking for real solutions to the original equation, and the domain on the right side is x>0, there is no solution.
There is no real solution to the equation. The graph of the functions:
Comments
Post a Comment